Verified Solution • 2025–26 Session moderate

QPages 230-234: Q26: HC Verma: Concepts of Physics - Volume 2 Magnetic Field Pages 230-234: Q26 Solution: Suppose that the radius of cross-section of the wire used in…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often apply Hooke's law as Δa = F/(Y A) and omit the necessary factor of the loop radius $a$, forgetting that strain is defined by $\Delta a/a = F/(Y A)$. Remember to multiply the stress $F/A$ by the original radius $a$ to obtain the absolute change, and use $A=\pi r^2$ for the wire’s cross‑section.

Suppose that the radius of cross-section of the wire used in the previous problem is rr. Find the increase in the radius of the loop if the magnetic field is switched off. Young's modulus of the material of the wire is YY.

Step-by-Step Verified Solution

**Answer:** Increase in radius Δa=iBa2YA\Delta a = \frac{i B a^2}{Y A}. **Step-by-Step Explanation:** The compression force causes a strain Δa/a=F/(YA)\Delta a/a = F/(YA). With F=iBaF = i B a, Δa=iBa2YA\Delta a = \frac{i B a^2}{Y A}.

All Questions in this Chapter

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