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QPages 98-102: Q37: HC Verma: Concepts of Physics - Volume 2 Heat Transfer Pages 98-102: Q37 Solution: Two bodies of masses and and specific heat capacities and are…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often write the solution as $\Delta T(t)=(T_2-T_1)e^{+\frac{KA}{l}\left(\frac1{m_1s_1}+\frac1{m_2s_2}\right)t}$, forgetting that heat flows from hot to cold, so $d\Delta T/dt$ is negative. Remember to include the minus sign in the exponent, yielding a decaying exponential.

Two bodies of masses m1m_1 and m2m_2 and specific heat capacities s1s_1 and s2s_2 are connected by a rod of length l, cross-sectional area A, thermal conductivity K and negligible heat capacity. The whole system is thermally insulated. At time t = 0, the temperature of the first body is T1T_1 and the temperature of the second body is T2T_2 T2>T1T_2 > T_1). Find the temperature difference between the two bodies at time t.

Step-by-Step Verified Solution

**Answer:** _T(t) = (T__T_) exp[_KA(1/m_s_ + 1/m_s_)t/l]. **Step-BY-Step Explanation:** The temperature difference decays exponentially:
ΔT(t)=(T2−T1)e−KAl(1m1s1+1m2s2)t\Delta T(t) = (T_2 - T_1) e^{-\frac{KA}{l}\left(\frac{1}{m_1s_1} + \frac{1}{m_2s_2}\right)t}

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