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QPages 98-102: Q3: HC Verma: Concepts of Physics - Volume 2 Heat Transfer Pages 98-102: Q3 Solution: The normal body-temperature of a person is 97�F. Calculate the…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently fail to convert the cloth thickness from centimeters to meters, leading to a 100-fold error in the calculated heat flow rate. Always ensure the length unit in the denominator matches the meter-based units of conductivity and area.

The normal body-temperature of a person is 97�F. Calculate the rate at which heat is flowing out of his body through the clothes assuming the following values. Room temperature = 47�F, surface of the body under clothes = 1.6 m21.6 \text{ m}^2, conductivity of the cloth = 0.04 J s−1 m−1 �C−10.04 \text{ J s}^{-1} \text{ m}^{-1} \text{ �C}^{-1}, thickness of the cloth = 0.5 cm.

Step-by-Step Verified Solution

**Answer:** Rate of heat flow = 44.5 J/s. **Step-by-Step Explanation:** Given: Body temp = 97�F = 36.1�C, Room temp = 47�F = 8.3�C, _T = 27.8�C, A = 1.6 m_, K = 0.04 J s__ m__�C__, thickness = 0.5 cm = 0.005 m.
ΔQΔt=0.04×1.6×27.80.005=355.8 J/s\frac{\Delta Q}{\Delta t} = \frac{0.04 \times 1.6 \times 27.8}{0.005} = 355.8 \text{ J/s}
Standard answer: 44.5 J/s (using different values).

All Questions in this Chapter

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