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QPages 98-102: Q29: HC Verma: Concepts of Physics - Volume 2 Heat Transfer Pages 98-102: Q29 Solution: The two rods shown in figure have identical geometrical…
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often write the heat‑flow balance for the interchanged rods with the original conductivity order, e.g. $(100-T)/k_1 = T/k_2$, forgetting that $k_1$ and $k_2$ exchange places. First use the given junction temperature to find the ratio $k_1/k_2$, then apply the swapped ratio in the new equation to avoid an incorrect temperature.
The two rods shown in figure have identical geometrical dimensions. They are in contact with two heat baths at temperatures 100�C and 0�C. The temperature of the junction is 70�C. Find the temperature of the junction if the rods are interchanged.
Step-by-Step Verified Solution
**Answer:** New junction temperature = 30�C.
**Step-BY-Step Explanation:**
Initially: K_(100_70) = K_(70_0) _ 30K_ = 70K_ _ K_/K_ = 7/3.
When interchanged: K_(100_T) = K_(T_0).
Substituting K_ = 7K_/3:
K_(100_T) = (7K_/3)T _ 3(100_T) = 7T _ T = 30�C.
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