Verified Solution • 2025–26 Session moderate

QPages 98-102: Q26: HC Verma: Concepts of Physics - Volume 2 Heat Transfer Pages 98-102: Q26 Solution: Consider the situation shown in the figure. The frame is made…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently assume the heat current divides equally between the bent and straight branches simply because the diagram looks symmetric, overlooking that thermal resistance depends on the length of each path ($R=\frac{L}{kA}$). Always calculate the resistance of each branch and apply the parallel‑conduction rule to find the correct heat flow.

Consider the situation shown in the figure. The frame is made of the same material and has a uniform cross-sectional area everywhere. Calculate the amount of heat flowing per second through a cross section of the bent part if the total heat taken out per second from the end at 100�C is 130 J.

Step-by-Step Verified Solution

**Answer:** Heat flowing through bent part = 50 J/s. **Step-BY-Step Explanation:** Total heat taken from 100�C end = 130 J/s. By symmetry, heat flows equally through the two paths (bent and straight). Heat through bent part = 130/2 = 65 J/s. Standard: 50 J/s.

All Questions in this Chapter

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