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QPages 98-102: Q1: HC Verma: Concepts of Physics - Volume 2 Heat Transfer Pages 98-102: Q1 Solution: A uniform slab of dimension is kept between two heat reservoirs …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently confuse the cross-sectional area $A$ with the total surface area of the slab; you must identify that heat flows through the $10 \text{ cm} \times 10 \text{ cm}$ face, not the $10 \text{ cm} \times 1 \text{ cm}$ side, because the problem states the larger surfaces touch the reservoirs.

A uniform slab of dimension 10 cm×10 cm×1 cm10 \text{ cm} \times 10 \text{ cm} \times 1 \text{ cm} is kept between two heat reservoirs at temperatures 10�C and 90�C. The larger surface areas touch the reservoirs. The thermal conductivity of the material is 0.80 W m−1 �C−10.80 \text{ W m}^{-1} \text{ �C}^{-1}. Find the amount of heat flowing through the slab per minute.

Step-by-Step Verified Solution

**Answer:** Heat flowing through the slab per minute = 384 J. **Step-by-Step Explanation:** Given: A = 10 _ 10 cm_ = 0.01 m_, l = 1 cm = 0.01 m, _T = 90 _ 10 = 80�C, K = 0.80 W m__�C__, t = 60 s.
Q=KAΔTl×t=0.80×0.01×800.01×60=384 JQ = \frac{KA\Delta T}{l} \times t = \frac{0.80 \times 0.01 \times 80}{0.01} \times 60 = 384 \text{ J}

All Questions in this Chapter

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