Verified Solution • 2025–26 Session moderate

QPages 165-170: Q7: HC Verma: Concepts of Physics - Volume 2 Capacitors Pages 165-170: Q7 Solution: Three capacitors having capacitances 20 �F, 30 �F and 40 �F are …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently calculate the battery work as $W=qV$ for a capacitor bank, forgetting that the stored energy (and thus the work done in an ideal circuit) is $W=\frac12 C_{eq}V^2$. Using $qV$ doubles the correct value and also leads to unit errors when the capacitances are given in µF.

Three capacitors having capacitances 20 �F, 30 �F and 40 �F are connected in series with a 12 V battery. Find the charge on each of the capacitors. How much work has been done by the battery in charging the capacitors?

Step-by-Step Verified Solution

**Answer:** Charge on each = 110 _C, Work done = 1.33×10−31.33 \times 10^{-3} J. **Step-by-Step Explanation:** In series, the equivalent capacitance is:
\frac{1}{C_{eq}} = \frac{1}{20} + \frac{1}{30} + \frac{1}{40} \Rightarrow C_{eq} = 9.23 \text{ _F}
Charge on each capacitor is the same: q=CeqV=9.23×12=110q = C_{eq}V = 9.23 \times 12 = 110 _C. Work done by battery: W=qV=110×10−6×12=1.33×10−3W = qV = 110 \times 10^{-6} \times 12 = 1.33 \times 10^{-3} J .

All Questions in this Chapter

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