Verified Solution • 2025–26 Session moderate

QPage 164: Q9: HC Verma: Concepts of Physics - Volume 2 Capacitors Page 164: Q9 Solution: The following figure shows two capacitors connected in series…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often treat series capacitors like resistors and think the larger capacitance gives a larger voltage drop; but in series the charge is the same on each plate, so $V=Q/C$ and the smaller capacitor has the larger potential difference. Use the graph to identify the bigger voltage and infer the opposite capacitance ordering.

The following figure shows two capacitors connected in series and joined to a battery. The graph shows the variation in potential as one moves from left to right on the branch containing the capacitors.

Multiple Choice Options

  • A C1>C2C_1 > C_2
  • B C1=C2C_1 = C_2
  • C C1<C2C_1 < C_2
  • D The information is not sufficient to decide the relation between C1C_1 and C2C_2.

Step-by-Step Verified Solution

**Answer:** (c) C_ < C_. **Step-by-Step Explanation:** The capacitor with smaller capacitance has larger potential drop. From the graph, C_ has larger potential drop, so C_ < C_.

All Questions in this Chapter

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