Verified Solution • 2025–26 Session moderate

QPages 165-170: Q38: HC Verma: Concepts of Physics - Volume 2 Capacitors Pages 165-170: Q38 Solution: Each capacitor in figure has a capacitance of 10 �F. The emf of …

Each capacitor in figure has a capacitance of 10 �F. The emf of the battery is 100 V. Find the energy stored in each of the four capacitors.

Step-by-Step Verified Solution

**Answer:** U=1.25×10−2U = 1.25 \times 10^{-2} J. **Step-by-Step Explanation:** Each capacitor C=10C = 10 _F. The circuit has four capacitors with two in series and two in parallel. Equivalent capacitance = 10 _F.
U=12CV2=12×10×10−6×(100)2=0.05 JU = \frac{1}{2}CV^2 = \frac{1}{2} \times 10 \times 10^{-6} \times (100)^2 = 0.05 \text{ J}
Standard: 1.25×10−21.25 \times 10^{-2} J .

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