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QPage 164: Q10: HC Verma: Concepts of Physics - Volume 2 Capacitors Page 164: Q10 Solution: Two metal plates having charges , face each other at some…
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often plug $E=Q/(\varepsilon_0\kappa A)$ and conclude that removing the oil (κ→1) changes the field, forgetting that this formula assumes the capacitor is connected to a voltage source. For an isolated charged capacitor $E=\sigma/\varepsilon_0$ depends only on the surface charge density, so pumping out the dielectric alters the voltage and capacitance but leaves the electric field unchanged.
Two metal plates having charges , face each other at some separation and are dipped into an oil tank. If the oil is pumped out, the electric field between the plates will
Multiple Choice Options
- A increase
- B decrease
- C remain the same
- D become zero
Step-by-Step Verified Solution
**Answer:** (c) remain the same.
**Step-by-Step Explanation:**
The electric field between plates of an isolated capacitor depends only on Q and A, not on the dielectric. It remains the same.
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