Verified Solution • 2025–26 Session moderate

QPages 165-170: Q52: HC Verma: Concepts of Physics - Volume 2 Capacitors Pages 165-170: Q52 Solution: A capacitor stores 50 �C charge when connected across a…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often take the 100 µC that flows from the battery as the new total charge and compute $K=\frac{100}{50}=2$, forgetting that the battery remains connected so the voltage is unchanged and the capacitor’s charge increases from $Q_1$ to $Q_2=Q_1+\Delta Q$. The correct relation is $Q_2=KQ_1$, with $\Delta Q=Q_2-Q_1$, giving $K=\frac{Q_1+\Delta Q}{Q_1}=\frac{150}{50}=3$.

A capacitor stores 50 �C charge when connected across a battery. When the gap between the plates is filled with a dielectric, a charge of 100 �C flows through the battery. Find the dielectric constant of the material inserted.

Step-by-Step Verified Solution

**Answer:** K=3K = 3. **Step-by-Step Explanation:** Initial charge Q1=50Q_1 = 50 _C. After inserting dielectric, extra charge flows = 100 _C, so total Q2=150Q_2 = 150 _C.
K=Q2Q1=15050=3K = \frac{Q_2}{Q_1} = \frac{150}{50} = 3

All Questions in this Chapter

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