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QPages 77-80: Q2: HC Verma: Concepts of Physics - Volume 2 Specific Heat Capacities of Gases Pages 77-80: Q2 Solution: 5 g of a gas is contained in a rigid container and is heated…

5 g of a gas is contained in a rigid container and is heated from 15�C to 25�C. Specific heat capacity of the gas at constant volume is 0.172 cal g−1 �C−10.172 \text{ cal g}^{-1} \text{ �C}^{-1} and the mechanical equivalent of heat is 4.2 J cal−14.2 \text{ J cal}^{-1}. Calculate the change in the internal energy of the gas.

Step-by-Step Verified Solution

**Answer:** Change in internal energy = 36.12 J. **Step-by-Step Explanation:** Given: m=5m = 5 g, ΔT=10�C\Delta T = 10�\text{C}, cv=0.172c_v = 0.172 cal/g-�C. For rigid container, W=0W = 0. So ΔU=Q\Delta U = Q.
Q=mcvΔT=5×0.172×10=8.6 calQ = m c_v \Delta T = 5 \times 0.172 \times 10 = 8.6 \text{ cal}
In joules: ΔU=8.6×4.2=36.12 J\Delta U = 8.6 \times 4.2 = 36.12 \text{ J} [citation:4].

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