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QPages 76-77: Q5: HC Verma: Concepts of Physics - Volume 2 Specific Heat Capacities of Gases Pages 76-77: Q5 Solution: 70 calories of heat are required to raise the temperature of 2…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often apply $C_p-C_v=R$ directly to the whole gas, subtracting only $RDelta T$ from $Q_p$. Remember that $R$ is the gas constant per mole, so for $n$ moles the correct relation is $Q_v=Q_p-nRDelta T$. Failing to multiply by $n$ leads to an over‑estimate of the heat at constant volume.

70 calories of heat are required to raise the temperature of 2 mole of an ideal gas at constant pressure from 30� C to 35� C. The amount of heat required to raise the temperature of the same gas through the same range at constant volume is

Multiple Choice Options

  • A 30 calories
  • B 50 calories
  • C 70 calories
  • D 90 calories

Step-by-Step Verified Solution

**Answer:** (b) 50 calories. **Step-by-Step Explanation:** Q_p = nC_p_T = 70 cal. Q_v = nC_v_T = n(C_p - R)_T = 70 - nR_T. For 2 moles and 5�C, nR_T = 2 _ 2 _ 5 = 20 cal. Q_v = 70 - 20 = 50 cal.

All Questions in this Chapter

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