Verified Solution • 2025–26 Session moderate

QPages 76-77: Q2: HC Verma: Concepts of Physics - Volume 2 Specific Heat Capacities of Gases Pages 76-77: Q2 Solution: For a solid with a small expansion coefficient,

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often think a solid’s negligible expansion makes $C_p=C_v$, but the thermodynamic identity $C_p-C_v= rac{V,T,alpha^2}{kappa_T}$ shows the difference is always positive, only very small when the expansion coefficient $alpha$ is small. Remember that $C_p$ is always slightly larger than $C_v$ for any material, even a solid with tiny thermal expansion.

For a solid with a small expansion coefficient,

Multiple Choice Options

  • A Cp−Cv=RC_p - C_v = R
  • B Cp=CvC_p = C_v
  • C CpC_p is slightly greater than CvC_v
  • D CpC_p is slightly less than CvC_v

Step-by-Step Verified Solution

**Answer:** (c) C_p is slightly greater than C_v. **Step-by-Step Explanation:** For a solid with small expansion coefficient, C_p - C_v is very small but positive. So C_p is slightly greater than C_v.

All Questions in this Chapter

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