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QPages 77-80: Q16: HC Verma: Concepts of Physics - Volume 2 Specific Heat Capacities of Gases Pages 77-80: Q16 Solution: The volume of an ideal gas ) is changed adiabatically from 4.00 …

The volume of an ideal gas γ=1.5\gamma = 1.5) is changed adiabatically from 4.00 litres to 3.00 litres. Find the ratio of a) the final pressure to the initial pressure and b) the final temperature to the initial temperature.

Step-by-Step Verified Solution

**Answer:** (a) P2/P1=1.54P_2/P_1 = 1.54 (b) T2/T1=1.154T_2/T_1 = 1.154. **Step-by-Step Explanation:** Given: γ=1.5\gamma = 1.5, V1=4V_1 = 4 L, V2=3V_2 = 3 L. (a) Adiabatic: P1V1γ=P2V2γP_1V_1^\gamma = P_2V_2^\gamma:
P2P1=(V1V2)γ=(43)1.5=1.54\frac{P_2}{P_1} = \left(\frac{V_1}{V_2}\right)^\gamma = \left(\frac{4}{3}\right)^{1.5} = 1.54
(b) T1V1γ−1=T2V2γ−1T_1V_1^{\gamma-1} = T_2V_2^{\gamma-1}:
T2T1=(V1V2)γ−1=(43)0.5=1.154\frac{T_2}{T_1} = \left(\frac{V_1}{V_2}\right)^{\gamma-1} = \left(\frac{4}{3}\right)^{0.5} = 1.154

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