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QPage 77: Q2: HC Verma: Concepts of Physics - Volume 2 Specific Heat Capacities of Gases Page 77: Q2 Solution: Let Q and W denote the amount of heat given to an ideal gas and …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often equate a constant temperature with zero heat transfer, writing Q=0, or think no work is done because ΔU=0. Remember that for an ideal gas in an isothermal process ΔU=0, so the heat supplied to the system equals the work done by it (Q=W), keeping sign conventions straight.

Let Q and W denote the amount of heat given to an ideal gas and the work done by it in an isothermal process.

Multiple Choice Options

  • A Q = 0
  • B W = 0
  • C Q ≠\neq W
  • D Q = W

Step-by-Step Verified Solution

**Answer:** (d) Q = W. **Step-by-Step Explanation:** For an isothermal process on an ideal gas, _U = 0. So Q = W.

All Questions in this Chapter

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