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Q3.18: NCERT Physics - Part 1 MOTION IN A PLANE 3.18 Solution: A particle starts from the origin at t = 0 s with a velocity of …
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often treat the x‑motion as linear (x = v_xt) and ignore that the initial x‑velocity is zero, so the position follows $x=\tfrac12 a_x t^2$; remembering to use the quadratic form prevents the wrong time solution.
A particle starts from the origin at t = 0 s with a velocity of 10.0 j m/s and moves in the x-y plane with a constant acceleration of (8.0i + 2.0j) m/s_. (a) At what time is the x-coordinate of the particle 16 m? What is the y-coordinate of the particle at that time? (b) What is the speed of the particle at the time?
Step-by-Step Verified Solution
**Answer:** (a) t = 2.0 s, y = 24 m. (b) v = 21.3 m/s.
**Step-by-Step Explanation:**
(a) x = 4t_ = 16 _ t = 2 s. y = 10t + t_ = 20 + 4 = 24 m. [citation:11]
(b) v = 8ti + (10 + 2t)j. At t = 2: v = 16i + 14j. |v| = �(256 + 196) = 21.3 m/s. [citation:11]
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