Verified Solution • 2025–26 Session
moderate
Q3.12: NCERT Physics - Part 1 MOTION IN A PLANE 3.12 Solution: The ceiling of a long hall is 25 m high. What is the maximum…
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often write the maximum height as $h=\frac{u\sin\theta}{2g}$, omitting the required square on the sine term; the correct expression is $h=\frac{u^{2}\sin^{2}\theta}{2g}$. Using the wrong formula gives an incorrect angle and thus an erroneous range.
The ceiling of a long hall is 25 m high. What is the maximum horizontal distance that a ball thrown with a speed of 40 m/s can go without hitting the ceiling of the hall?
Step-by-Step Verified Solution
**Answer:** Maximum horizontal distance = 150.6 m.
**Step-by-Step Explanation:**
Maximum height h = u_sin__/(2g) � 25 m.
sin__ � 25 _ 2 _ 9.8 / 1600 = 0.306. sin_ = 0.553, _ = 33.6�.
Range R = u_sin2_/g = 1600 _ sin(67.2�)/9.8 = 150.6 m.
All Questions in this Chapter
Related Learning Resources & Exam Preparation
Chapter Practice Bank
Practice all topic-wise questions from MOTION IN A PLANE
Reference Textbook Solutions
Explore complete chapter exercises for NCERT Physics - Part 1
Competitive PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring