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Q3.13: NCERT Physics - Part 1 MOTION IN A PLANE 3.13 Solution: A cricketer can throw a ball to a maximum horizontal distance…
⚠️ Common Exam Traps & Conceptual Pitfalls
Students often write the range as $R=\frac{u}{g}$, forgetting that the correct expression is $R=\frac{u^{2}\sin2\theta}{g}$ (maximum $R=\frac{u^{2}}{g}$). Remember the initial speed appears squared; only then can you equate $u^{2}=Rg$ and find the true maximum height $H=\frac{u^{2}}{2g}=\frac{R}{2}$.
A cricketer can throw a ball to a maximum horizontal distance of 100 m. How much high above the ground can the cricketer throw the same ball?
Step-by-Step Verified Solution
**Answer:** Maximum height = 50 m.
**Step-by-Step Explanation:**
Maximum range R = u_/g = 100 m, so u_ = 100g.
For maximum height, throw vertically: H = u_/(2g) = 100g/(2g) = 50 m.
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