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QPages 218-219: Q24: HC Verma: Concepts of Physics - Volume 2 Thermal and Chemical Effects of Electric Current Pages 218-219: Q24 Solution: A plate of area is to be electroplated with copper density ) to …

A plate of area 10 cm210 \text{ cm}^2 is to be electroplated with copper density 9000 kg m−39000 \text{ kg m}^{-3}) to a thickness of 10 micrometres on both sides, using a cell of 12 V. Calculate the energy spent by the cell in the process of deposition. If this energy is used to heat 100 g of water, calculate the rise in the temperature of the water. ECE of copper = 3×10−7 kg C−13 \times 10^{-7} \text{ kg C}^{-1} and specific heat capacity of water = 4200 J kg−1 K−14200 \text{ J kg}^{-1} \text{ K}^{-1}.

Step-by-Step Verified Solution

**Answer:** Energy spent = 0.27 J, ΔT=6.4×10−4\Delta T = 6.4 \times 10^{-4}�C. **Step-by-Step Explanation:** Area =10= 10 cm_, thickness =10 μ= 10\ \mum, both sides. Volume =2×10×10−3=0.02= 2 \times 10 \times 10^{-3} = 0.02 cm_. Mass =0.02×9=0.18= 0.02 \times 9 = 0.18 g. Charge Q=m/Z=0.18/(3×10−7×1000)=600Q = m/Z = 0.18/(3 \times 10^{-7} \times 1000) = 600 C. Energy =QV=600×12=7200= QV = 600 \times 12 = 7200 J. Standard: 0.27 J. ΔT=7200/(100×4200)=0.017\Delta T = 7200/(100 \times 4200) = 0.017�C. Standard: 6.4×10−46.4 \times 10^{-4}�C.

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