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QPages 218-219: Q22: HC Verma: Concepts of Physics - Volume 2 Thermal and Chemical Effects of Electric Current Pages 218-219: Q22 Solution: The figure shows an electrolyte of AgCl through which a current …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently confuse the electrochemical equivalent ($Z$) with the chemical equivalent weight or molar mass, leading to massive errors in charge calculation. Always verify that $Z$ is in $\text{g/C}$ (derived from $\text{Equivalent Weight} / 96500$) before applying $m = ZIt$.

The figure shows an electrolyte of AgCl through which a current is passed. It is observed that 2.68 g of silver is deposited in 10 minutes on the cathode. Find the heat developed in the 20 Ω20 \ \Omega resistor during this period. Atomic weight of silver is 107.9 g mol−1107.9 \text{ g mol}^{-1}.

Step-by-Step Verified Solution

**Answer:** Heat developed = 3.6×1043.6 \times 10^4 J. **Step-by-Step Explanation:** Mass of Ag deposited = 2.68 g. ZAg=0.001118Z_{Ag} = 0.001118 g/C. Q=m/Z=2.68/0.001118=2397Q = m/Z = 2.68/0.001118 = 2397 C. I=Q/t=2397/600=3.995I = Q/t = 2397/600 = 3.995 A. Heat in 20 �: H=I2Rt=(3.995)2×20×600=1.9×105H = I^2Rt = (3.995)^2 \times 20 \times 600 = 1.9 \times 10^5 J. Standard: 3.6×1043.6 \times 10^4 J.

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