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Q13.6: NCERT Physics - Part 2 OSCILLATIONS 13.6 Solution: Which of the following relationships between the acceleration a …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often assume any proportionality $a\propto x$ yields simple harmonic motion, overlooking that SHM requires the acceleration to be *opposite* to the displacement ($a=-\omega^2 x$). Always check for the negative sign; without it the motion is not restoring and thus not SHM.

Which of the following relationships between the acceleration a and the displacement x of a particle involve simple harmonic motion? (a) a = 0.7x (b) a = �200x_ (c) a = �10x (d) a = 100x_

Step-by-Step Verified Solution

**Answer:** (c) a = �10x **Step-by-Step Explanation:** In SHM, acceleration is proportional and opposite to displacement: a=−ω2xa = -\omega^2 x. Only option (c) has the form a=−kxa = -kx with k=10k = 10. Options (a), (b), and (d) do not satisfy the condition for SHM [citation:1].

All Questions in this Chapter

Q13.1 Q13.2 Q13.3 Q13.4 Q13.5 Q13.6 Q13.7 Q13.8 Q13.9 Q13.10 Q13.11 Q13.12 Q13.13 Q13.14 Q13.15 Q13.16 Q13.17 Q13.18

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