Q13.5: NCERT Physics - Part 2 OSCILLATIONS 13.5 Solution: A particle is in linear simple harmonic motion between two…

**Answer:** (a) v = 0, a = +, F = + (b) v = 0, a = �, F = � (c) v = �, a = 0, F = 0 (d) v = �, a = �, F = � (e) v = +, a = +, F = + (f) v = �, a = +, F = + **Step-by-Step Explanation:** Let O be the midpoint (mean position), A and B the extremes. (a) At end A: Particle is momentarily at rest, so $v = 0$. Acceleration and force are directed towards O (positive direction), so $a = +$, $F = +$ [citation:13]. (b) At end B: Particle is momentarily at rest, so $v = 0$. Acceleration and force are directed towards O (negative direction), so $a = �$, $F = �$ [citation:13]. (c) At midpoint O going towards A: Velocity is along negative direction, so $v = �$. At mean position, $a = 0$, $F = 0$ [citation:13]. (d) At 2 cm from B going towards A: Velocity is towards A (negative direction), so $v = �$. Acceleration and force are directed towards O (negative direction), so $a = �$, $F = �$ [citation:13]. (e) At 3 cm from A going towards B: Velocity is towards B (positive direction), so $v = +$. Acceleration and force are directed towards O (positive direction), so $a = +$, $F = +$ [citation:13]. (f) At 4 cm from B going towards A: Velocity is towards A (negative direction), so $v = �$. Acceleration and force are directed towards O (positive direction), so $a = +$, $F = +$ [citation:13].