Verified Solution • 2025–26 Session moderate

Q13.11: NCERT Physics - Part 2 OSCILLATIONS 13.11 Solution: Figures 13.20 correspond to two circular motions. The radius of …

Figures 13.20 correspond to two circular motions. The radius of the circle, the period of revolution, the initial position, and the sense of revolution (i.e. clockwise or anti-clockwise) are indicated on each figure. Obtain the corresponding simple harmonic motions of the x-projection of the radius vector of the revolving particle P, in each case.

Step-by-Step Verified Solution

**Answer:** (a) x=−3sin⁡(πt)x = -3\sin(\pi t) cm (b) x=−2cos⁡(πt/2)x = -2\cos(\pi t/2) cm **Step-by-Step Explanation:** (a) Radius = 3 cm, period = 2 s, initial position at 9 o'clock (leftmost point). The particle starts from the negative extreme. ω=2π/T=2π/2=π\omega = 2\pi/T = 2\pi/2 = \pi rad/s. The x-projection is: x=−3sin⁡(πt)x = -3\sin(\pi t) cm [citation:9]. (b) Radius = 2 cm, period = 4 s, initial position at 12 o'clock (topmost point). The particle starts from the mean position. ω=2π/4=π/2\omega = 2\pi/4 = \pi/2 rad/s. The x-projection is: x=−2cos⁡(πt/2)x = -2\cos(\pi t/2) cm [citation:9].

All Questions in this Chapter

Q13.1 Q13.2 Q13.3 Q13.4 Q13.5 Q13.6 Q13.7 Q13.8 Q13.9 Q13.10 Q13.11 Q13.12 Q13.13 Q13.14 Q13.15 Q13.16 Q13.17 Q13.18

Related Learning Resources & Exam Preparation

Chapter Practice Bank
Practice all topic-wise questions from OSCILLATIONS
Reference Textbook Solutions
Explore complete chapter exercises for NCERT Physics - Part 2
Competitive PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring