Verified Solution • 2025–26 Session moderate

Q6.9: NCERT Physics - Part 1 SYSTEMS OF PARTICLES AND ROTATIONAL MOTION 6.9 Solution: A car weighs 1800 kg. The distance between its front and back…

A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.

Step-by-Step Verified Solution

**Answer:** Front wheels: 3675 N each. Back wheels: 5145 N each. **Step-by-Step Explanation:** Let RfR_f and RbR_b be total normal forces on front and back wheels.
Rf+Rb=1800×10=18000 NR_f + R_b = 1800 \times 10 = 18000 \text{ N}
Taking torques about the front axle:
Rb×1.8=18000×1.05⇒Rb=10500 NR_b \times 1.8 = 18000 \times 1.05 \Rightarrow R_b = 10500 \text{ N}
Rf=18000−10500=7500 NR_f = 18000 - 10500 = 7500 \text{ N}
Each front wheel: 7500/2=37507500/2 = 3750 N. Each back wheel: 10500/2=525010500/2 = 5250 N. Standard answer (using g = 9.8): Front = 3675 N, Back = 5145 N.

All Questions in this Chapter

Q6.1 Q6.2 Q6.3 Q6.4 Q6.5 Q6.6 Q6.7 Q6.8 Q6.9 Q6.10 Q6.11 Q6.12 Q6.13 Q6.14 Q6.15 Q6.16 Q6.17

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