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Q6.16: NCERT Physics - Part 1 SYSTEMS OF PARTICLES AND ROTATIONAL MOTION 6.16 Solution: A metre stick is balanced on a knife edge at its centre. When…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often take the stick’s weight to act at the knife‑edge or at the wrong point after the balance shifts; the correct torque arm is the distance from the stick’s centre of mass (the 50 cm mark for a uniform metre stick) to the new pivot at 45 cm. Use the centre of mass, not the end or the pivot, when writing the torque equation.

A metre stick is balanced on a knife edge at its centre. When two coins, each of mass 5 g are put one on top of the other at the 12.0 cm mark, the stick is found to be balanced at 45.0 cm. What is the mass of the metre stick?

Step-by-Step Verified Solution

**Answer:** Mass of metre stick = 66 g. **Step-by-Step Explanation:** Taking torques about the 45 cm mark:
10 g×(45−12)=m×(50−45)10 \text{ g} \times (45 - 12) = m \times (50 - 45)
10×33=5m  ⟹  m=66 g10 \times 33 = 5m \implies m = 66 \text{ g}
[citation:28]

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