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Q6.11: NCERT Physics - Part 1 SYSTEMS OF PARTICLES AND ROTATIONAL MOTION 6.11 Solution: A solid cylinder of mass 20 kg rotates about its axis with…

A solid cylinder of mass 20 kg rotates about its axis with angular speed 100 rad s__. The radius of the cylinder is 0.25 m. What is the kinetic energy associated with the rotation of the cylinder? What is the magnitude of angular momentum of the cylinder about its axis?

Step-by-Step Verified Solution

**Answer:** KE = 3125 J, L = 62.5 kg m_/s. **Step-by-Step Explanation:** Moment of inertia of solid cylinder: I=12MR2=12(20)(0.25)2=0.625 kg m2I = \frac{1}{2}MR^2 = \frac{1}{2}(20)(0.25)^2 = 0.625 \text{ kg m}^2. KE: K=12Iω2=12(0.625)(100)2=3125 JK = \frac{1}{2}I\omega^2 = \frac{1}{2}(0.625)(100)^2 = 3125 \text{ J}. Angular momentum: L=Iω=0.625×100=62.5 kg m2/sL = I\omega = 0.625 \times 100 = 62.5 \text{ kg m}^2/\text{s}.

All Questions in this Chapter

Q6.1 Q6.2 Q6.3 Q6.4 Q6.5 Q6.6 Q6.7 Q6.8 Q6.9 Q6.10 Q6.11 Q6.12 Q6.13 Q6.14 Q6.15 Q6.16 Q6.17

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