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Q7.6: NCERT Physics - Part 1 GRAVITATION 7.6 Solution: Choose the correct alternative: (a) If the zero of potential…

Choose the correct alternative: (a) If the zero of potential energy is at infinity, the total energy of an orbiting satellite is negative of its kinetic/potential energy. (b) The energy required to launch an orbiting satellite out of earth's gravitational influence is more/less than the energy required to project a stationary object at the same height (as the satellite) out of earth's influence.

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**Answer:** (a) Kinetic energy (b) Less **Step-by-Step Explanation:** (a) Total mechanical energy of a satellite is the sum of its kinetic energy (always positive) and potential energy (may be negative). At infinity, the gravitational potential energy is zero. For a bound system, total energy is negative. Thus, total energy = negative of kinetic energy [citation:10][citation:15]. (b) For a stationary object at height hh, energy required = GMm/(R+h)GMm/(R+h). For an orbiting satellite at the same height, total energy = −GMm/2(R+h)-GMm/2(R+h), so energy required = GMm/2(R+h)GMm/2(R+h). This is half the energy required for the stationary object. Hence, less energy is needed [citation:10][citation:15].

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