Verified Solution • 2025–26 Session moderate

Q7.20: NCERT Physics - Part 1 GRAVITATION 7.20 Solution: Two stars each of one solar mass ( kg) are approaching each…

Two stars each of one solar mass (=2×1030= 2 \times 10^{30} kg) are approaching each other for a head on collision. When they are a distance 10910^9 km, their speeds are negligible. What is the speed with which they collide? The radius of each star is 10410^4 km. Assume the stars to remain undistorted until they collide. (Use the known value of G).

Step-by-Step Verified Solution

**Answer:** 6.4×1056.4 \times 10^5 m/s **Step-by-Step Explanation:** Using conservation of energy. Initial energy (at distance d=109d = 10^9 km):
Ei=−GMMd=−GM2dE_i = -\frac{GMM}{d} = -\frac{GM^2}{d}
Final energy (at separation 2R=2×1072R = 2 \times 10^7 m, each moving with speed vv):
Ef=−GM22R+2×12Mv2E_f = -\frac{GM^2}{2R} + 2 \times \frac{1}{2}Mv^2
Equating:
Mv2=GM2(12R−1d)Mv^2 = GM^2\left(\frac{1}{2R} - \frac{1}{d}\right)
v=GM(12R−1d)=(6.67×10−11)(2×1030)(12×107−11012)=6.4×105 m/sv = \sqrt{GM\left(\frac{1}{2R} - \frac{1}{d}\right)} = \sqrt{(6.67 \times 10^{-11})(2 \times 10^{30})\left(\frac{1}{2 \times 10^7} - \frac{1}{10^{12}}\right)} = 6.4 \times 10^5 \text{ m/s}

All Questions in this Chapter

Related Learning Resources & Exam Preparation