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QPages 286-287: Q6: HC Verma: Concepts of Physics - Volume 2 Magnetic Properties of Matter Pages 286-287: Q6 Solution: The magnetic field B and the magnetic intensity H in a material …

The magnetic field B and the magnetic intensity H in a material are found to be 1.6 T and 1000 A m−11000 \text{ A m}^{-1}, respectively. Calculate the relative permeability μr\mu_r and the susceptibility χ\chi of the material.

Step-by-Step Verified Solution

**Answer:** μr≈1.3×103\mu_r \approx 1.3 \times 10^3, χ≈1.3×103\chi \approx 1.3 \times 10^3. **Step-BY-Step Explanation:** Given: B=1.6 TB = 1.6 \text{ T}, H=1000 A/mH = 1000 \text{ A/m}.
μ=BH=1.61000=1.6×10−3 T m/A\mu = \frac{B}{H} = \frac{1.6}{1000} = 1.6 \times 10^{-3} \text{ T m/A}
μr=μμ0=1.6×10−34π×10−7≈1273≈1.3×103\mu_r = \frac{\mu}{\mu_0} = \frac{1.6 \times 10^{-3}}{4\pi \times 10^{-7}} \approx 1273 \approx 1.3 \times 10^3
χ=μr−1≈1.3×103\chi = \mu_r - 1 \approx 1.3 \times 10^3

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