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QPages 338-339: Q5: HC Verma: Concepts of Physics - Volume 2 Electromagnetic Waves Pages 338-339: Q5 Solution: An electromagnetic wave going through vacuum is described by ;…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often confuse the amplitude relation $E_0/B_0=c$ with the wave‑parameter relation, mistakenly writing $E_0\,\omega = B_0\,k$ or $E_0=B_0$. Remember that Maxwell’s curl equation gives $kE_0=\omega B_0$, i.e. $E_0 k = B_0 \omega$, not a direct proportionality between $E_0$ and $B_0$ alone.

An electromagnetic wave going through vacuum is described by

E = E_0 \sin kx - \omega t)

;

B = B_0 \sin kx - \omega t)

. Which of the following equations is true?

Multiple Choice Options

A $E_0 k = B_0 \omega$
B $E_0 B_0 = \omega k$
C $E_0 \omega = B_0 k$
D None of these

Step-by-Step Verified Solution

**Answer:** (a) E_k = B__. **Step-by-Step Explanation:** For an electromagnetic wave, E_/B_ = c = _/k. So E_k = B__.

All Questions in this Chapter

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