Verified Solution • 2025–26 Session
moderate
QPage 339: Q2: HC Verma: Concepts of Physics - Volume 2 Electromagnetic Waves Page 339: Q2 Solution: A point charge is moving along a straight line with a constant…
⚠️ Common Exam Traps & Conceptual Pitfalls
When the charge approaches the area, $x$ decreases so $dx/dt=-v$. Forgetting the minus sign gives $d(x^{-2})/dt=-2v/x^3$ and a spurious negative displacement current; use $d(x^{-2})/dt=2v/x^3$ to obtain the correct positive magnitude.
A point charge is moving along a straight line with a constant velocity . Consider a small area perpendicular to the motion of the charge. Calculate the displacement current through the area when its distance from the charge is . The value of is not large, so that the electric field at any instant is essentially given by Coulomb's law.
Step-by-Step Verified Solution
**Answer:**
**Step-by-Step Explanation:**
The electric field at distance from a point charge is .
The electric flux through area perpendicular to the motion is .
Displacement current: .
Since (charge approaching), .
Thus, [citation:3][citation:4].
All Questions in this Chapter
QPage 338: Q1
QPage 338: Q2
QPage 338: Q3
QPage 338: Q4
QPage 338: Q5
QPage 338: Q6
QPage 338: Q7
QPage 339: Q1
QPage 339: Q1
QPage 339: Q2
QPage 339: Q2
QPage 339: Q3
QPage 339: Q3
QPage 339: Q4
QPage 339: Q4
QPage 339: Q5
QPage 339: Q5
QPage 339: Q6
QPage 339: Q7
QPage 339: Q8
QPage 339: Q9
QPages 338-339: Q1
QPages 338-339: Q2
QPages 338-339: Q3
QPages 338-339: Q4
QPages 338-339: Q5
QPages 338-339: Q6
QPages 338-339: Q7
QPages 338-339: Q8
QPages 338-339: Q9
Related Learning Resources & Exam Preparation
Chapter Practice Bank
Practice all topic-wise questions from Electromagnetic Waves
Reference Textbook Solutions
Explore complete chapter exercises for HC Verma: Concepts of Physics - Volume 2
Competitive PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring