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QPages 352-354: Q21: HC Verma: Concepts of Physics - Volume 2 Electric Current through Gases Pages 352-354: Q21 Solution: A triode has mutual conductance of 2.0 millimho and plate…

A triode has mutual conductance of 2.0 millimho and plate resistance of 20 kΩ20 \text{ k}\Omega. It is desired to amplify a signal by a factor of 30. What load resistance should be added in the circuit?

Step-by-Step Verified Solution

**Answer:** Load resistance RL=15 kΩR_L = 15 \text{ k}\Omega. **Step-by-Step Explanation:** Given: gm=2.0g_m = 2.0 millimho, rp=20 kΩr_p = 20 \text{ k}\Omega, amplification desired A=30A = 30.
A=μRLrp+RL=gmrpRLrp+RLA = \frac{\mu R_L}{r_p + R_L} = \frac{g_m r_p R_L}{r_p + R_L}
30=0.002×20000×RL20000+RL=40RL20000+RL30 = \frac{0.002 \times 20000 \times R_L}{20000 + R_L} = \frac{40 R_L}{20000 + R_L}
600000+30RL=40RL⇒10RL=600000⇒RL=60000Ω=60 kΩ600000 + 30R_L = 40R_L \Rightarrow 10R_L = 600000 \Rightarrow R_L = 60000 \Omega = 60 \text{ k}\Omega
Standard: 15 k� .

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