QPage 48-49: Q7: HC Verma: Concepts of Physics - Volume 1 Chapter-3 Rest and Motion Kinematics Page 48-49: Q7 Solution: Two particles A and B start from rest and move for equal time…
Two particles A and B start from rest and move for equal time on a straight line. The particle A has an acceleration a for the first half .....
Step-by-Step Verified Solution
Step 1: Define the variables
Let:
- Total time of motion = T
- For each particle, the motion is divided into two equal halves:
- First half: time = T/2
- Second half: time = T/2
Let a be some positive constant (acceleration).
Step 2: Particle A
First half (0 to T/2):
- Initial velocity: u₁ = 0
- Acceleration: a₁ = a
- Time: t₁ = T/2
Final velocity after first half:
v₁ = u₁ + a₁t₁ = 0 + a(T/2) = aT/2
Distance covered in first half:
s₁ = u₁t₁ + ½a₁t₁² = 0 + ½(a)(T/2)² = aT²/8
Second half (T/2 to T):
- Initial velocity: u₂ = v₁ = aT/2
- Acceleration: a₂ = 2a
- Time: t₂ = T/2
Distance covered in second half:
s₂ = u₂t₂ + ½a₂t₂²
s₂ = (aT/2)(T/2) + ½(2a)(T/2)²
s₂ = aT²/4 + a(T²/4)
s₂ = aT²/4 + aT²/4 = aT²/2
Total distance for Particle A:
S_A = s₁ + s₂ = aT²/8 + aT²/2
S_A = aT²/8 + 4aT²/8 = 5aT²/8
Step 3: Particle B
First half (0 to T/2):
- Initial velocity: u₁ = 0
- Acceleration: a₁ = 2a
- Time: t₁ = T/2
Final velocity after first half:
v₁ = u₁ + a₁t₁ = 0 + (2a)(T/2) = aT
Distance covered in first half:
s₁ = u₁t₁ + ½a₁t₁² = 0 + ½(2a)(T/2)²
s₁ = a(T²/4) = aT²/4
Second half (T/2 to T):
- Initial velocity: u₂ = v₁ = aT
- Acceleration: a₂ = a
- Time: t₂ = T/2
Distance covered in second half:
s₂ = u₂t₂ + ½a₂t₂²
s₂ = (aT)(T/2) + ½(a)(T/2)²
s₂ = aT²/2 + aT²/8
s₂ = 4aT²/8 + aT²/8 = 5aT²/8
Total distance for Particle B:
S_B = s₁ + s₂ = aT²/4 + 5aT²/8
S_B = 2aT²/8 + 5aT²/8 = 7aT²/8
Step 4: Compare
Particle | Total Distance |
A | 5aT²/8 |
B | 7aT²/8 |
Clearly:
S_B > S_A
Step 5: Intuitive Explanation
Why does Particle B cover more distance even though both use the same two accelerations (a and 2a) for equal times?
- Particle B gets the larger acceleration (2a) first, when it is starting from rest.
- This gives it a higher velocity early on.
- Even though its second-half acceleration is smaller (a), it enters the second half with a much larger initial speed (aT vs. aT/2 for Particle A).
- Since distance depends heavily on initial velocity (especially in the second half), Particle B maintains a significant lead.
In contrast, Particle A gets the smaller acceleration first, so it is slower during the entire first half and never catches up.
Final Answer
Particle B covers the larger distance.
Particle | Total Distance |
A | 5aT²/8 |
B | 7aT²/8 |
So, B > A by a margin of aT²/4.