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Q8.16: NCERT Physics - Part 2 MECHANICAL PROPERTIES OF SOLIDS 8.16 Solution: How much should the pressure on a litre of water be changed to…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently read “0.10 %” as 0.01 or 0.10 instead of the correct fractional change $0.10% = 10^{-3}=0.001$, producing a ten‑ to hundred‑fold error in $Delta P$. Always convert the percent to a decimal fraction before applying $\Delta P = B\,\Delta V/V$, and keep volume units in m³ for consistency with the bulk modulus.

How much should the pressure on a litre of water be changed to compress it by 0.10%?

Step-by-Step Verified Solution

**Answer:** ΔP=2.2×106\Delta P = 2.2 \times 10^6 Pa **Step-by-Step Explanation:** V=1V = 1 L =10−3= 10^{-3} m_, ΔV/V=0.10%=10−3\Delta V/V = 0.10\% = 10^{-3}, B=2.2×109B = 2.2 \times 10^9 Pa.
ΔP=B×ΔVV=2.2×109×10−3=2.2×106 Pa\Delta P = B \times \frac{\Delta V}{V} = 2.2 \times 10^9 \times 10^{-3} = 2.2 \times 10^6 \text{ Pa}

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