Verified Solution • 2025–26 Session moderate

Q8.15: NCERT Physics - Part 2 MECHANICAL PROPERTIES OF SOLIDS 8.15 Solution: Determine the volume contraction of a solid copper cube, 10 cm…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently omit the negative sign in the formula $\Delta V = -\frac{PV}{B}$, treating the result as a positive expansion. You must explicitly include the negative sign to indicate volume contraction under compressive pressure, or clearly state the magnitude as a contraction.

Determine the volume contraction of a solid copper cube, 10 cm on an edge, when subjected to a hydraulic pressure of 7.0×106 Pa7.0 \times 10^6 \text{ Pa}.

Step-by-Step Verified Solution

**Answer:** ΔV=−4.9×10−8\Delta V = -4.9 \times 10^{-8} m_ **Step-by-Step Explanation:** V=(0.1)3=10−3V = (0.1)^3 = 10^{-3} m_, P=7.0×106P = 7.0 \times 10^6 Pa, BCu=140×109B_{Cu} = 140 \times 10^9 Pa.
ΔV=−PVB=−7.0×106×10−3140×109=−5.0×10−8 m3\Delta V = -\frac{PV}{B} = -\frac{7.0 \times 10^6 \times 10^{-3}}{140 \times 10^9} = -5.0 \times 10^{-8} \text{ m}^3
Standard answer: −4.9×10−8-4.9 \times 10^{-8} m_ [citation:36].

All Questions in this Chapter

Q8.1 Q8.2 Q8.3 Q8.4 Q8.5 Q8.6 Q8.7 Q8.8 Q8.9 Q8.10 Q8.11 Q8.12 Q8.13 Q8.14 Q8.15 Q8.16

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