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Q14.12: NCERT Physics - Part 2 WAVES 14.12 Solution: (i) For the wave on a string described in Exercise 14.11, do…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often incorrectly assume that because all points in a stationary wave oscillate with the same frequency, they must also share the same phase and amplitude. You must recognize that while frequency is uniform, amplitude varies spatially according to the envelope function, and phase is only identical for points within the same loop (between adjacent nodes).

(i) For the wave on a string described in Exercise 14.11, do all the points on the string oscillate with the same (a) frequency, (b) phase, (c) amplitude? Explain your answers. (ii) What is the amplitude of a point 0.375 m away from one end?

Step-by-Step Verified Solution

**Answer:** (a) Yes (b) Yes (c) No. (ii) A=0.042A = 0.042 m. **Step-by-Step Explanation:** (i) For the stationary wave described, all points between two consecutive nodes vibrate with: - Same frequency (a): Yes, all vibrate with frequency 60 Hz. - Same phase (b): Yes, all points in the same loop are in phase. - Same amplitude (c): No, amplitude varies from zero at nodes to maximum at antinodes [citation:2][citation:15]. (ii) Amplitude at x=0.375x = 0.375 m:
A(x)=0.06sin⁡(2π×0.3753)=0.06sin⁡(π4)=0.06×0.707=0.042 mA(x) = 0.06\sin\left(\frac{2\pi \times 0.375}{3}\right) = 0.06\sin\left(\frac{\pi}{4}\right) = 0.06 \times 0.707 = 0.042 \text{ m}
[citation:2][citation:15]

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