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Q10.13: NCERT Physics - Part 2 THERMAL PROPERTIES OF MATTER 10.13 Solution: A copper block of mass 2.5 kg is heated in a furnace to a…

A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 �C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper = 0.39 J g__ K__; heat of fusion of water = 335 J g__).

Step-by-Step Verified Solution

**Answer:** Mass of ice melted = 1.45 kg **Step-by-Step Explanation:** Heat lost by copper block = mcΔT=2.5×0.39×500=487.5mc\Delta T = 2.5 \times 0.39 \times 500 = 487.5 kJ. Mass of ice melted = QL=487.5×103335×103=1.455\frac{Q}{L} = \frac{487.5 \times 10^3}{335 \times 10^3} = 1.455 kg. [citation:2]

All Questions in this Chapter

Q10.1 Q10.2 Q10.3 Q10.4 Q10.5 Q10.6 Q10.7 Q10.8 Q10.9 Q10.10 Q10.11 Q10.12 Q10.13 Q10.14 Q10.15 Q10.16 Q10.17 Q10.18 Q10.19 Q10.20

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