Verified Solution • 2025–26 Session moderate

Q10.1: THERMAL PROPERTIES OF MATTER Solutions — NCERT Physics - Part 2

⚠️ Common Exam Traps & Conceptual Pitfalls

When converting negative Celsius temperatures to Fahrenheit, ensure the $+32$ offset is added after scaling, as students frequently subtract 32 or ignore the sign change, leading to incorrect magnitudes for sub-zero values.

The triple points of neon and carbon dioxide are 24.57 K and 216.55 K respectively. Express these temperatures on the Celsius and Fahrenheit scales.

Step-by-Step Verified Solution

**Answer:** Neon: −248.58∘C-248.58^\circ\text{C}, −415.44∘F-415.44^\circ\text{F}. Carbon dioxide: −56.60∘C-56.60^\circ\text{C}, −69.88∘F-69.88^\circ\text{F}. **Step-by-Step Explanation:** The Kelvin and Celsius scales are related by:
TC=TK−273.15T_C = T_K - 273.15
The Celsius and Fahrenheit scales are related by:
TF=95TC+32T_F = \frac{9}{5}T_C + 32
For neon: TK=24.57T_K = 24.57 K
TC=24.57−273.15=−248.58∘CT_C = 24.57 - 273.15 = -248.58^\circ\text{C}
TF=95(−248.58)+32=−415.44∘FT_F = \frac{9}{5}(-248.58) + 32 = -415.44^\circ\text{F}
For carbon dioxide: TK=216.55T_K = 216.55 K
TC=216.55−273.15=−56.60∘CT_C = 216.55 - 273.15 = -56.60^\circ\text{C}
TF=95(−56.60)+32=−69.88∘FT_F = \frac{9}{5}(-56.60) + 32 = -69.88^\circ\text{F}
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All Questions in this Chapter

Q10.1 Q10.2 Q10.3 Q10.4 Q10.5 Q10.6 Q10.7 Q10.8 Q10.9 Q10.10 Q10.11 Q10.12 Q10.13 Q10.14 Q10.15 Q10.16 Q10.17 Q10.18 Q10.19 Q10.20

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