Verified Solution • 2025–26 Session moderate

Q5.20: NCERT Physics - Part 1 WORK, ENERGY AND POWER 5.20 Solution: A body of mass 0.5 kg travels in a straight line with velocity…

A body of mass 0.5 kg travels in a straight line with velocity v = ax^(3/2) where a = 5 m^(-1/2) s__. What is the work done by the net force during its displacement from x = 0 to x = 2 m?

Step-by-Step Verified Solution

**Answer:** W = 50 J **Step-by-Step Explanation:** At x = 0, v = 0. At x = 2 m:
v=5×23/2=5×2.828=14.14 m/sv = 5 \times 2^{3/2} = 5 \times 2.828 = 14.14 \text{ m/s}
Work done = change in kinetic energy:
W=12mv2−0=12×0.5×(14.14)2=50 JW = \frac{1}{2}mv^2 - 0 = \frac{1}{2} \times 0.5 \times (14.14)^2 = 50 \text{ J}

All Questions in this Chapter

Q5.1 Q5.2 Q5.3 Q5.4 Q5.5 Q5.6 Q5.7 Q5.8 Q5.9 Q5.10 Q5.11 Q5.12 Q5.13 Q5.14 Q5.15 Q5.16 Q5.17 Q5.18 Q5.19 Q5.20 Q5.21 Q5.22 Q5.23

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