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Q2.3: NCERT Physics - Part 1 MOTION IN A STRAIGHT LINE 2.3 Solution: A woman starts from her home at 9.00 am, walks with a speed of…

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When drawing the return leg, the slope must be negative because the position decreases with time. The slope is Δx/Δt, so for a move from 2.5 km back to 0 km in 0.1 h the slope is (0–2.5)/0.1 = –25 km/h; a positive slope would incorrectly make the graph rise instead of fall.

A woman starts from her home at 9.00 am, walks with a speed of 5 km h�1 on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm, and returns home by an auto with a speed of 25 km h�1. Choose suitable scales and plot the x-t graph of her motion.

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**Answer:** The x-t graph will have three segments: a straight line with slope 5 km/h from 9:00 am to 9:30 am, a horizontal line from 9:30 am to 5:00 pm, and a straight line with negative slope 25 km/h from 5:00 pm to 5:06 pm. **Step-by-Step Explanation:** Time to reach office = Distance/Speed = 2.5/5 = 0.5 h = 30 min. She reaches at 9:30 am. She stays at office from 9:30 am to 5:00 pm (7.5 hours). Return time = 2.5/25 = 0.1 h = 6 min. She reaches home at 5:06 pm. [citation:1] The graph has: (i) a line from (0, 0) to (0.5 h, 2.5 km), (ii) a horizontal line from (0.5 h, 2.5 km) to (8 h, 2.5 km), (iii) a line from (8 h, 2.5 km) to (8.1 h, 0).

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