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Q4.7: NCERT Physics - Part 1 LAWS OF MOTION 4.7 Solution: A body of mass 5 kg is acted upon by two perpendicular forces 8 …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently add the magnitudes 8 N + 6 N as if the forces were collinear, yielding a wrong resultant; remember that perpendicular forces must be combined vectorially using $F=\sqrt{8^2+6^2}$ and the direction follows $ an\theta=6/8$, not by simple arithmetic.

A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.

Step-by-Step Verified Solution

**Answer:** a = 2 m/s_, at angle tan__(3/4) with the 8 N force **Step-by-Step Explanation:** Resultant force:
F=82+62=64+36=10 NF = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = 10 \text{ N}
Acceleration:
a=Fm=105=2 m/s2a = \frac{F}{m} = \frac{10}{5} = 2 \text{ m/s}^2
Direction: tan⁡θ=6/8=3/4\tan \theta = 6/8 = 3/4, so _ = tan__(3/4) with the 8 N force [citation:10].

All Questions in this Chapter

Q4.1 Q4.2 Q4.3 Q4.4 Q4.5 Q4.6 Q4.7 Q4.8 Q4.9 Q4.10 Q4.11 Q4.12 Q4.13 Q4.14 Q4.15 Q4.16 Q4.17 Q4.18 Q4.19 Q4.20 Q4.21 Q4.22 Q4.23

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