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QPages 456-457: Q5: HC Verma: Concepts of Physics - Volume 2 The Special Theory of Relativity Pages 456-457: Q5 Solution: A person travelling in a fast spaceship measures the distance…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often confuse the moving observer's frame with the proper length frame, incorrectly assuming the spaceship measures the maximum distance. Remember that proper length $L_0$ is defined only in the frame where the endpoints (Earth and Moon) are at rest, so any other inertial frame will measure a contracted length $L < L_0$.

A person travelling in a fast spaceship measures the distance between the earth and the moon. Is it the same, smaller or larger than the value quoted in this book?

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**Answer:** The distance measured by the person in the spaceship will be **smaller** than the value quoted in the book. **Step-by-Step Explanation:** The distance between the earth and the moon is measured in the earth-moon rest frame, which is essentially the earth frame. This is the proper length L0L_0. For an observer in a fast-moving spaceship, the distance is length-contracted:
L=L01−v2c2<L0L = L_0\sqrt{1 - \frac{v^2}{c^2}} < L_0
Hence, the person in the spaceship measures a smaller distance .

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