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QPage 47: Q14: HC Verma: Concepts of Physics - Volume 2 Calorimetry Page 47: Q14 Solution: A block of mass 100 g slides on a rough horizontal surface. If…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students frequently fail to convert the mass from grams to kilograms before applying the kinetic energy formula, leading to an answer that is 1000 times too large. Always ensure mass is in SI units (kg) when calculating energy in Joules.

A block of mass 100 g slides on a rough horizontal surface. If the speed of the block decreases from 10 m s−110 \text{ m s}^{-1} to 5 m s−15 \text{ m s}^{-1}, find the thermal energy developed in the process.

Step-by-Step Verified Solution

**Answer:** Thermal energy developed = 3.75 J. **Step-by-Step Explanation:** Given: Mass of block = 100 g = 0.1 kg; Initial speed = 10 m/s; Final speed = 5 m/s. Change in kinetic energy:
ΔKE=12×0.1×102−12×0.1×52=5−1.25=3.75 J\Delta KE = \frac{1}{2} \times 0.1 \times 10^2 - \frac{1}{2} \times 0.1 \times 5^2 = 5 - 1.25 = 3.75 \text{ J}
Thermal energy developed = 3.75 J.[citation:2]

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