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QPages 141-142: Q20: HC Verma: Concepts of Physics - Volume 2 Gauss's Law Pages 141-142: Q20 Solution: One end of a 10 cm long silk thread is fixed to a large…

One end of a 10 cm long silk thread is fixed to a large vertical surface of a charged non-conducting plate and the other end is fastened to a small ball of mass 10 g and a charge of 4.0×10−6 C4.0 \times 10^{-6} \text{ C}. In equilibrium, the thread makes an angle of 60� with the vertical a) Find the tension in the string in equilibrium. b) Suppose the ball is slightly pushed aside and released. Find the time period of the small oscillations.

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**Answer:** (a) T=0.2T = 0.2 N (b) T=0.63T = 0.63 s. **Step-BY-STEP Explanation:** (a) Tcos⁡60�=mg⇒T=0.01×100.5=0.2T\cos 60� = mg \Rightarrow T = \frac{0.01 \times 10}{0.5} = 0.2 N. (b) For small oscillations, the effective restoring force includes both gravity and electric force. The time period is:
T=2πlgeffT = 2\pi\sqrt{\frac{l}{g_{eff}}}
where geff=g2+(qE/m)2g_{eff} = \sqrt{g^2 + (qE/m)^2}. Standard: 0.63 s.

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