HC Verma: Concepts of Physics - Volume 2 Gauss's Law Pages 139-140: Q7 Solution: A charge q is placed at the centre of the open end of a…

QPages 139-140: Q7: HC Verma: Concepts of Physics - Volume 2 Gauss's Law Pages 139-140: Q7 Solution: A charge q is placed at the centre of the open end of a…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often apply Gauss's law as if the cylindrical vessel were a closed surface and assign the full $q/\varepsilon_0$ flux, forgetting that the charge sits on the open end so only the solid angle of $2\pi$ sr (half space) contributes. Remember that Gauss's law gives total flux through a *closed* surface; for an open surface you must take the fraction of the total solid angle intercepted, which here is one‑half, yielding $q/(2\varepsilon_0)$.

A charge q is placed at the centre of the open end of a cylindrical vessel see the figure). The flux of the electric field through the surface of the vessel is ____________.

Multiple Choice Options

A zero
B $q/\varepsilon_0$
C $q/2\varepsilon_0$
D $2q/\varepsilon_0$

Step-by-Step Verified Solution

**Answer:** (c) q/(2__). **Step-by-Step Explanation:** The flux through the open end of the cylinder is q/(2__) by symmetry (half the total flux).

QPages 139-140: Q7: HC Verma: Concepts of Physics - Volume 2 Gauss's Law Pages 139-140: Q7 Solution: A charge q is placed at the centre of the open end of a…

Multiple Choice Options

Step-by-Step Verified Solution

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