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QPages 384-386: Q27: HC Verma: Concepts of Physics - Volume 2 Bohr's Model and Physics of the Atom Pages 384-386: Q27 Solution: A beam of light having wavelengths distributed uniformly…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often incorrectly assume that hydrogen gas at room temperature only absorbs Lyman series photons (transitions from $n=1$), leading them to conclude no visible light is absorbed. You must recognize that the Balmer series ($n=2 \to n>2$) falls within the visible spectrum and that a non-negligible fraction of hydrogen atoms are thermally excited to the $n=2$ state, allowing absorption of the 486 nm photon.

A beam of light having wavelengths distributed uniformly between 450 nm to 550 nm passes through a sample of hydrogen gas. Which wavelength will have the least intensity in the transmitted beam?

Step-by-Step Verified Solution

**Answer:** Wavelength = 486 nm will have least intensity. **Step-by-Step Explanation:** The light has wavelengths 450�550 nm. Hydrogen gas at room temperature has electrons in n = 1. Absorption occurs when photon energy matches a transition from n = 1. The Lyman series lines are at 121.6 nm, 102.6 nm, etc., all in UV. So no absorption occurs in the 450�550 nm range. Wait�the question says least intensity in transmitted beam," which implies absorption. The Balmer series lines are at 656 nm, 486 nm, 434 nm, etc. 486 nm n=4_2) falls in the 450�550 nm range. So this wavelength will be absorbed, reducing intensity.

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