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QPages 384-386: Q11: HC Verma: Concepts of Physics - Volume 2 Bohr's Model and Physics of the Atom Pages 384-386: Q11 Solution: Find the maximum Coulomb force that can act on the electron due …

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often mistakenly use the Bohr radius formula $r_n = n^2 a_0$ without recognizing that the maximum force corresponds to the minimum radius, which occurs specifically at the ground state ($n=1$). Always verify that you are substituting $n=1$ to find the smallest orbital radius before calculating the inverse-square force.

Find the maximum Coulomb force that can act on the electron due to the nucleus in a hydrogen atom.

Step-by-Step Verified Solution

**Answer:** Maximum Coulomb force = 8.2 _ 10__ N. **Step-by-Step Explanation:** The maximum force occurs at the smallest radius (n = 1):
F=ke2r2=9×109×(1.6×10−19)2(0.53×10−10)2=8.2×10−8 NF = \frac{ke^2}{r^2} = \frac{9 \times 10^9 \times (1.6 \times 10^{-19})^2}{(0.53 \times 10^{-10})^2} = 8.2 \times 10^{-8} \text{ N}
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