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QPage 383: Q11: HC Verma: Concepts of Physics - Volume 2 Bohr's Model and Physics of the Atom Page 383: Q11 Solution: A hydrogen atom in ground state absorbs 10.2 eV of energy. The…

⚠️ Common Exam Traps & Conceptual Pitfalls

Students often try to compute the angular‑momentum change from the absorbed energy instead of using the Bohr rule $L=n\hbar$. The correct increase is simply $\Delta L=(2-1)\hbar=\hbar\approx1.05\times10^{-34}\,$J·s; any energy‑to‑momentum conversion leads to a wrong answer.

A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by

Multiple Choice Options

  • A 1.05×10−34 J s1.05 \times 10^{-34} \text{ J s}
  • B 2.11×10−34 J s2.11 \times 10^{-34} \text{ J s}
  • C 3.16×10−34 J s3.16 \times 10^{-34} \text{ J s}
  • D 4.22×10−34 J s4.22 \times 10^{-34} \text{ J s}

Step-by-Step Verified Solution

**Answer:** (a) 1.05 _ 10___ J s. **Step-by-Step Explanation:** The electron is excited from n=1 to n=2. The angular momentum changes from _ to 2_, an increase of _ = 1.05 _ 10___ J s.

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