QNEET-2024-Ph-72: NEET 2024 Physics - Class 12 NEET-2024-Ph-72 Solution: A small telescope has an objective of focal length 140 cm and…

The magnifying power of a telescope when viewing distant objects can be calculated using the formula: Magnifying Power ( M ) = Focal Length of Objective Lens ( f o ) Focal Length of Eyepiece Lens ( f e ) Given in the problem: Focal Length of Objective Lens, f o = 140   c m $f_o = 140 \mathrm{~cm}$ f o _ = 140   cm Focal Length of Eyepiece Lens, f e = 5.0   c m $f_e = 5.0 \mathrm{~cm}$ f e _ = 5.0   cm Substituting these values into the formula gives: M = 140   cm 5.0   cm = 28 Thus, the magnifying power of the telescope is 28 . The correct answer is Option B .